JEE Main 2021 · MathsMultiple choiceSingle correctMediumCalculation

JEE Main 27 August 2021, Shift 1, Maths Q65

Question 65 of 90 in this shift, Maths question 5 of 30, Section A.

\alpha

\beta

are the distinct roots of

x^2+bx+c=0

, then

\lim_{x\to\beta}\frac{e^{2(x^2+bx+c)}-1-2(x^2+bx+c)}{(x-\beta)^2}

is equal to :

(1) $b^2-4c$
(2) $b^2+4c$
(3) $2(b^2+4c)$
(4) $2(b^2-4c)$ Official answer

Official answer

Option 4

NTA final key.

Chapter: Limits and Derivatives
Topic: L'Hopital's Rule
Idea tested: Choosing Series Expansion over L'Hopital

Same idea in other shifts

Asked 10× in all

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.