JEE Main 2026 · PhysicsNumerical answerNumerical valueEasyCalculation

JEE Main 5 April 2026, Shift 2, Physics Q49

Question 49 of 75 in this shift, Physics question 24 of 25, Section B.

When an external resistance of 5

\Omega

is connected across terminals of a cell, a current of 0.25 A flows through it. When the 5

\Omega

resistor is replaced by a 2

\Omega

resistor, a current of 0.5 A flows through it. The internal resistance of the cell is __________

\Omega

Official answer

NTA final key.

Chapter: Current Electricity
Topic: Kirchhoff's Laws
Idea tested: Cell EMF and Internal Resistance

Same idea in other shifts

Asked 3× in all

8 Apr 2024, Shift 1 · Q40In the given circuit, the terminal potential difference of the cell is :EasySingle correctHas a figure
31 Jan 2024, Shift 2 · Q56In the following circuit, the battery has an emf of 2V and an internal resistance of $\frac{2}{3}\Omega$ . The power consumption in the…MediumNumerical valueHas a figure

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.