JEE Main 2024 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 8 April 2024, Shift 1, Physics Q40

Question 40 of 90 in this shift, Physics question 10 of 30, Section A.

In the given circuit, the terminal potential difference of the cell is :

The figure, in words

Circuit: a cell of emf 3 V with internal resistance 1 ohm (enclosed in dashed box) connected across two 4 ohm resistors in parallel.

(1) $2\ \mathrm{V}$ Official answer
(2) $3\ \mathrm{V}$
(3) $4\ \mathrm{V}$
(4) $1.5\ \mathrm{V}$

Official answer

Option 1

NTA final key.

Chapter: Current Electricity
Topic: Kirchhoff's Laws
Idea tested: Cell EMF and Internal Resistance

Same idea in other shifts

Asked 3× in all

5 Apr 2026, Shift 2 · Q49When an external resistance of 5 $\Omega$ is connected across terminals of a cell, a current of 0.25 A flows through it. When the 5…EasyNumerical value
31 Jan 2024, Shift 2 · Q56In the following circuit, the battery has an emf of 2V and an internal resistance of $\frac{2}{3}\Omega$ . The power consumption in the…MediumNumerical valueHas a figure

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.