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Friday, 9 October

JEE Main 2025 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 8 April 2025, Shift 2, Maths Q12

Question 12 of 75 in this shift, Maths question 12 of 25, Section A.

Let the ellipse 3x2+py2=43x^2 + py^2 = 4 pass through the centre CC of the circle x2+y2−2x−4y−11=0x^2 + y^2 - 2x - 4y - 11 = 0 of radius rr. Let f1,f2f_1, f_2 be the focal distances of the point CC on the ellipse. Then 6f1f2−r6f_1f_2 - r is equal to
  1. (1)74
  2. (2)70Official answer
  3. (3)68
  4. (4)78

Official answer

Option 2

NTA final key.

Chapter
Conic Sections
Topic
Ellipse Eccentricity
Idea tested
Product of Focal Distances

Same idea in other shifts

Asked 2× in all
  1. 2 Apr 2025, Shift 1 · Q4If S and S' are the foci of the ellipse x218+y29=1\frac{x^2}{18}+\frac{y^2}{9}=1 and P be a point on the ellipse, then…MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.