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JEE Main 2025 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 2 April 2025, Shift 1, Maths Q4

Question 4 of 75 in this shift, Maths question 4 of 25, Section A.

If S and S' are the foci of the ellipse

\frac{x^2}{18}+\frac{y^2}{9}=1

and P be a point on the ellipse, then

\min(\mathrm{SP}\cdot\mathrm{S'P})+\max(\mathrm{SP}\cdot\mathrm{S'P})

is equal to :

(1) $3(1+\sqrt{2})$
(2) $3(6+\sqrt{2})$
(3)9
(4)27Official answer

Official answer

Option 4

NTA final key.

Chapter: Conic Sections
Topic: Ellipse Eccentricity
Idea tested: Product of Focal Distances

Same idea in other shifts

Asked 2× in all

8 Apr 2025, Shift 2 · Q12Let the ellipse $3x^2 + py^2 = 4$ pass through the centre $C$ of the circle $x^2 + y^2 - 2x - 4y - 11 = 0$ of radius $r$ . Let $f_1, f_2$ …MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.