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Friday, 9 October

JEE Main 2025 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 7 April 2025, Shift 2, Maths Q15

Question 15 of 75 in this shift, Maths question 15 of 25, Section A.

Let a⃗\vec{a} and b⃗\vec{b} be the vectors of the same magnitude such that ∣a⃗+b⃗∣+∣a⃗−b⃗∣∣a⃗+b⃗∣−∣a⃗−b⃗∣=2+1\frac{|\vec{a}+\vec{b}|+|\vec{a}-\vec{b}|}{|\vec{a}+\vec{b}|-|\vec{a}-\vec{b}|}=\sqrt{2}+1. Then ∣a⃗+b⃗∣2∣a⃗∣2\frac{|\vec{a}+\vec{b}|^2}{|\vec{a}|^2} is :
  1. (1)2+22+\sqrt{2}Official answer
  2. (2)4+224+2\sqrt{2}
  3. (3)1+21+\sqrt{2}
  4. (4)2+422+4\sqrt{2}

Official answer

Option 1

NTA final key.