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Friday, 9 October

JEE Main 2024 · MathsMultiple choiceSingle correctEasyApplication

JEE Main 30 January 2024, Shift 2, Maths Q18

Question 18 of 90 in this shift, Maths question 18 of 30, Section A.

Let a⃗\vec{a} and b⃗\vec{b} be two vectors such that ∣b⃗∣=1|\vec{b}| = 1 and ∣b⃗×a⃗∣=2|\vec{b} \times \vec{a}| = 2. Then ∣(b⃗×a⃗)−b⃗∣2\left|(\vec{b} \times \vec{a}) - \vec{b}\right|^2 is equal to
  1. (1)11
  2. (2)33
  3. (3)44
  4. (4)55Official answer

Official answer

Option 4

NTA final key.