JEE Main 2025 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 7 April 2025, Shift 1, Physics Q41

Question 41 of 75 in this shift, Physics question 16 of 25, Section A.

Two plane polarized light waves combine at a certain point whose electric field components are

E_1 = E_0 \sin\omega t

E_2 = E_0 \sin\left(\omega t + \frac{\pi}{3}\right)

Find the amplitude of the resultant wave.

(1) $1.7\,E_0$ Official answer
(2) $E_0$
(3) $0.9\,E_0$
(4) $3.4\,E_0$

Official answer

Option 1

NTA final key.

Chapter: Wave Optics
Topic: Young's Double Slit
Idea tested: Resultant Intensity Formula

Same idea in other shifts

Asked 5× in all

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.