JEE Main 2025 · PhysicsNumerical answerNumerical valueEasyCalculation

JEE Main 3 April 2025, Shift 1, Physics Q50

Question 50 of 75 in this shift, Physics question 25 of 25, Section B.

Two coherent monochromatic light beams of intensities 4I and 9I are superimposed. The difference between the maximum and minimum intensities in the resulting interference pattern is

x

I. The value of

x

is ______.

Official answer

NTA final key.

Chapter: Wave Optics
Topic: Young's Double Slit
Idea tested: Resultant Intensity Formula

Same idea in other shifts

Asked 5× in all

7 Apr 2025, Shift 1 · Q41Two plane polarized light waves combine at a certain point whose electric field components are $E_1 = E_0 \sin\omega t$ …EasySingle correct
6 Apr 2024, Shift 2 · Q54Two coherent monochromatic light beams of intensities $I$ and $4I$ are superimposed. The difference between maximum and minimum possible…EasyNumerical value
31 Jan 2024, Shift 1 · Q59Two waves of intensity ratio 1:9 cross each other at a point. The resultant intensities at that point, when (a) Waves are incoherent is…MediumNumerical value
13 Apr 2023, Shift 2 · Q46In a Young's double slits experiment, the ratio of amplitude of light coming from slits is 2:1. The ratio of the maximum to minimum…EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.