JEE Main 2024 · ChemistryNumerical answerNumerical valueEasyCalculation
JEE Main 31 January 2024, Shift 1, Chemistry Q84
Question 84 of 90 in this shift, Chemistry question 24 of 30, Section B.
Consider the following reaction at 298 K. . . for the reaction is _________ kJ. (Given R = 8.314 J K mol)
Official answer
163
NTA final key.
- Chapter
- Thermodynamics (Chemistry)
- Topic
- Gibbs Free Energy
- Idea tested
- Gibbs Energy and Equil