JEE Main 2024 · ChemistryNumerical answerNumerical valueEasyCalculation
JEE Main 1 February 2024, Shift 2, Chemistry Q82
Question 82 of 90 in this shift, Chemistry question 22 of 30, Section B.
For a certain reaction at 300K, K = 10, then for the same reaction is ________ kJ mol. (Given R = 8.314 J K mol)
Official answer
57
NTA final key.
- Chapter
- Thermodynamics (Chemistry)
- Topic
- Gibbs Free Energy
- Idea tested
- Gibbs Energy and Equil