JEE Main 2024 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 30 January 2024, Shift 1, Maths Q12

Question 12 of 90 in this shift, Maths question 12 of 30, Section A.

Let

y=y(x)

be the solution of the differential equation

\sec x\,dy+\{2(1-x)\tan x+x(2-x)\}dx=0

such that

y(0)=2

. Then

y(2)

is equal to :

(1) $1$
(2) $2$ Official answer
(3) $2\{\sin(2)+1\}$
(4) $2\{1-\sin(2)\}$

Official answer

Option 2

NTA final key.

Chapter: Differential Equations
Topic: Linear Differential Equations
Idea tested: Exact Differential Recognition in LDEs

Same idea in other shifts

Asked 3× in all

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27 Aug 2021, Shift 1 · Q71Let us consider a curve, $y=f(x)$ passing through the point $(-2, 2)$ and the slope of the tangent to the curve at any point $(x, f(x))$ …MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.