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Saturday, 31 October

JEE Main 2022 · MathsMultiple choiceSingle correctHardMulti-step

JEE Main 26 June 2022, Shift 2, Maths Q9

Question 9 of 90 in this shift, Maths question 9 of 30, Section A.

If y=y(x)y = y(x) is the solution of the differential equation xdydx+2y=xexx\frac{dy}{dx} + 2y = x e^x, y(1)=0y(1) = 0 then the local maximum value of the function z(x)=x2y(x)−exz(x) = x^2 y(x) - e^x, x∈Rx \in \mathbb{R} is :
  1. (1)1−e1 - e
  2. (2)00
  3. (3)12\frac{1}{2}
  4. (4)4e−e\frac{4}{e} - eOfficial answer

Official answer

Option 4

NTA final key.