JEE Main 2024 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 29 January 2024, Shift 1, Physics Q43

Question 43 of 90 in this shift, Physics question 13 of 30, Section A.

A capacitor of capacitance

100\ \mu

F is charged to a potential of 12 V and connected to a 6.4 mH inductor to produce oscillations. The maximum current in the circuit would be :

(1) $1.2$ A
(2) $3.2$ A
(3) $1.5$ AOfficial answer
(4) $2.0$ A

Official answer

Option 3

NTA final key.

Chapter: Alternating Current
Topic: LCR Resonance
Idea tested: LC Energy Oscillation at Resonance

Same topic in other shifts

All LCR Resonance questions

5 Apr 2026, Shift 2 · Q48A series LCR circuit with $R=20\ \Omega$ , $L=1.6$ H and $C=40\ \mu\mathrm{F}$ is connected to a variable frequency a.c. source. The…EasyNumerical value
6 Apr 2024, Shift 2 · Q59For a given series LCR circuit it is found that maximum current is drawn when value of variable capacitance is 2.5 nF. If resistance of…EasyNumerical value
8 Apr 2024, Shift 1 · Q50A LCR circuit is at resonance for a capacitor C, inductance L and resistance R. Now the value of resistance is halved keeping all other…EasySingle correct
8 Apr 2023, Shift 2 · Q58A series combination of resistor of resistance 100 $\Omega$ , inductor of inductance 1 H and capacitor of capacitance 6.25 $\mu$ F is…EasyNumerical value
11 Apr 2023, Shift 1 · Q36As per the given graph, choose the correct representation for curve A and curve B. {Where $X_C$ = reactance of pure capacitive circuit…EasyDiagram basedHas a figure
25 Jul 2022, Shift 1 · Q42To increase the resonant frequency in series LCR circuit,EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.