JEE Main 2022 · PhysicsNumerical answerNumerical valueEasyCalculation

JEE Main 29 July 2022, Shift 2, Physics Q60

Question 60 of 90 in this shift, Physics question 30 of 30, Section B.

A capacitor of capacitance 500

\mu

F is charged completely using a dc supply of 100 V. It is now connected to an inductor of inductance 50 mH to form an LC circuit. The maximum current in LC circuit will be ___ A.

Official answer

NTA final key.

Chapter: Alternating Current
Topic: LCR Resonance
Idea tested: LC Energy Oscillation at Resonance

Same idea in other shifts

Asked 3× in all

29 Jan 2024, Shift 1 · Q43A capacitor of capacitance $100\ \mu$ F is charged to a potential of 12 V and connected to a 6.4 mH inductor to produce oscillations. The…EasySingle correct
8 Apr 2023, Shift 1 · Q57An oscillating LC circuit consists of a $75\ \mathrm{mH}$ inductor and a $1.2\ \mu\mathrm{F}$ capacitor. If the maximum charge to the…EasyNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.