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Saturday, 31 October

JEE Main 2024 · PhysicsNumerical answerNumerical valueEasyCalculation

JEE Main 27 January 2024, Shift 1, Physics Q58

Question 58 of 90 in this shift, Physics question 28 of 30, Section B.

Two coils have mutual inductance 0.002 H. The current changes in the first coil according to the relation i=i0sin⁡ωti = i_0\sin\omega t, where i0i_0 = 5 A and ω\omega = 50π50\pi rad/s. The maximum value of emf in the second coil is πα\frac{\pi}{\alpha} V. The value of α\alpha is ________.

Official answer

2

NTA final key.