Learn

Friday, 9 October

JEE Main 2026 · PhysicsMultiple choiceSingle correctHardMulti-step

JEE Main 2 April 2026, Shift 2, Physics Q43

Question 43 of 75 in this shift, Physics question 18 of 25, Section A.

A circular current loop of radius R is placed inside square loop of side length L (L >> R) such that they are co-planar and their centers coincide. The permeability of free space is μ0\mu_0. The mutual inductance between circular loop and square loop is
  1. (1)22μ0L2R2\sqrt{2}\frac{\mu_0 L^2}{R}
  2. (2)2μ0L2R\sqrt{2}\frac{\mu_0 L^2}{R}
  3. (3)2μ0R2L\sqrt{2}\frac{\mu_0 R^2}{L}
  4. (4)22μ0R2L2\sqrt{2}\frac{\mu_0 R^2}{L}Official answer

Official answer

Option 4

NTA final key.

Same idea in other shifts

Asked 2× in all
  1. 25 Jul 2022, Shift 1 · Q43A small square loop of wire of side ll is placed inside a large square loop of wire LL (L≫lL\gg l). Both loops are coplanar and their…HardDiagram basedHas a figure

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.