JEE Main 2024 · PhysicsNumerical answerNumerical valueMediumApplication

JEE Main 1 February 2024, Shift 2, Physics Q55

Question 55 of 90 in this shift, Physics question 25 of 30, Section B.

Suppose a uniformly charged wall provides a uniform electric field of

2\times10^4

N/C normally. A charged particle of mass 2 g being suspended through a silk thread of length 20 cm and remain stayed at a distance of 10 cm from the wall. Then the charge on the particle will be

\frac{1}{\sqrt{x}}\ \mu

C where

x =

________. [use

g = 10\ \mathrm{m/s^2}

]

Official answer

NTA final key.

Chapter: Electric Charges and Fields
Topic: Electric Field
Idea tested: Equilibrium of Suspended Charges

Same topic in other shifts

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.