JEE Main 2024 (9 Apr, Shift 1) Maths Q9: Area Under Curves

Question

The parabola $y^2=4x$ divides the area of the circle $x^2+y^2=5$ in two parts. The area of the smaller part is equal to :

Accepted Answer

Option 4: $\frac{2}{3}+5\sin^{-1}\left(\frac{2}{\sqrt{5}}\right)$

Answer

$\frac{1}{3}+\sqrt{5}\sin^{-1}\left(\frac{2}{\sqrt{5}}\right)$

Answer

$\frac{2}{3}+\sqrt{5}\sin^{-1}\left(\frac{2}{\sqrt{5}}\right)$

Answer

$\frac{1}{3}+5\sin^{-1}\left(\frac{2}{\sqrt{5}}\right)$

Answer

$\frac{2}{3}+5\sin^{-1}\left(\frac{2}{\sqrt{5}}\right)$

JEE Main 9 April 2024, Shift 1, Maths Q9