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Friday, 9 October

JEE Main 2024 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 9 April 2024, Shift 1, Maths Q10

Question 10 of 90 in this shift, Maths question 10 of 30, Section A.

The solution of the differential equation (x2+y2)dx−5xy dy=0(x^2+y^2)dx-5xy\,dy=0, y(1)=0y(1)=0, is :
  1. (1)∣x2−2y2∣6=x\left|x^2-2y^2\right|^6=x
  2. (2)∣x2−2y2∣5=x2\left|x^2-2y^2\right|^5=x^2
  3. (3)∣x2−4y2∣6=x\left|x^2-4y^2\right|^6=x
  4. (4)∣x2−4y2∣5=x2\left|x^2-4y^2\right|^5=x^2Official answer

Official answer

Option 4

NTA final key.

Chapter
Differential Equations
Topic
Homogeneous Equations
Idea tested
Substitution y = vx

Same idea in other shifts

Asked 5× in all
  1. 5 Apr 2026, Shift 1 · Q25Let y=y(x)y = y(x) be the solution of the differential equation…HardNumerical value
  2. 28 Jul 2022, Shift 1 · Q1Let the solution curve of the differential equation x dy=(x2+y2+y)dx, x>0x\,dy=\left(\sqrt{x^2+y^2}+y\right)dx,\ x>0, intersect the line x=1x=1 at y=0y=0 and…MediumSingle correct
  3. 29 Jun 2022, Shift 1 · Q2Let the solution curve of the differential equation xdydx−y=y2+16x2x\frac{dy}{dx} - y = \sqrt{y^2 + 16x^2}, y(1)=3y(1) = 3 be y=y(x)y = y(x). Then y(2)y(2) is…MediumSingle correct
  4. 9 Jan 2020, Shift 2 · Q64If dydx=xyx2+y2\frac{dy}{dx}=\frac{xy}{x^2+y^2}; y(1)=1y(1)=1; then a value of xx satisfying y(x)=ey(x)=e is :MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.