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Friday, 9 October

JEE Main 2024 · MathsNumerical answerNumerical valueMediumMulti-step

JEE Main 6 April 2024, Shift 2, Maths Q30

Question 30 of 90 in this shift, Maths question 30 of 30, Section B.

In a triangle ABCABC, BC=7BC=7, AC=8AC=8, AB=α∈NAB=\alpha\in\mathbb{N} and cos⁡A=23\cos A=\frac{2}{3}. If 49cos⁡(3C)+42=mn49\cos(3C)+42=\frac{m}{n}, where gcd⁡(m,n)=1\gcd(m,n)=1, then m+nm+n is equal to ________.

Official answer

39

NTA final key.