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JEE Main 2024 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 29 January 2024, Shift 1, Maths Q14

Question 14 of 90 in this shift, Maths question 14 of 30, Section A.

Let

\left(5,\frac{a}{4}\right)

be the circumcenter of a triangle with vertices

A(a,-2)

,

B(a,6)

and

C\left(\frac{a}{4},-2\right)

. Let

\alpha

denote the circumradius,

\beta

denote the area and

\gamma

denote the perimeter of the triangle. Then

\alpha+\beta+\gamma

is

(1) $30$
(2) $60$
(3) $62$
(4) $53$ Official answer

Official answer

Option 4

NTA final key.

Chapter: Straight Lines
Topic: Properties of Triangles
Idea tested: Inradius and Circumradius

Same idea in other shifts

Asked 2× in all

16 Mar 2021, Shift 2 · Q82In $\triangle$ ABC, the lengths of sides AC and AB are 12 cm and 5 cm, respectively. If the area of $\triangle$ ABC is 30 $\mathrm{cm^2}$ …MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.