The major products from the following reaction sequence are product A and product B. [figure: cyclohexene; upper arrow to the right (i) $\mathrm{Br_2}$, (ii) HC≡C–CH$_2$–O$^-$Na$^+$ (1.0 eq.) gives A; arrow to the left (i) $\mathrm{Br_2}$, (ii) alc. KOH (3 eq.) gives B] The total sum of $\pi$ electrons in product A and product B are __________ (nearest integer)

JEE Main 2024 · ChemistryNumerical answerNumerical valueHardMulti-step

JEE Main 6 April 2024, Shift 1, Chemistry Q89

Question 89 of 90 in this shift, Chemistry question 29 of 30, Section B.

The major products from the following reaction sequence are product A and product B. [figure: cyclohexene; upper arrow to the right (i)

\mathrm{Br_2}

, (ii) HC≡C–CH

_2

–O

^-

^+

(1.0 eq.) gives A; arrow to the left (i)

\mathrm{Br_2}

, (ii) alc. KOH (3 eq.) gives B] The total sum of

\pi

electrons in product A and product B are __________ (nearest integer)

The figure, in words

Cyclohexene in the centre. Right arrow: (i) Br2, (ii) a sodium alkoxide drawn as an alkyne with CH2 and O-Na+ (1.0 eq.), giving A. Left arrow: (i) Br2, (ii) alc. KOH (3 eq.), giving B.

Official answer

NTA final key.

Chapter: Haloalkanes and Haloarenes
Topic: Alkenes and Alkynes
Idea tested: Alkyne Synthesis via Double Elimination

Same topic in other shifts

All Alkenes and Alkynes questions

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.