JEE Main 2024 · MathsMultiple choiceSingle correctHardMulti-step

JEE Main 6 April 2024, Shift 1, Maths Q6

Question 6 of 90 in this shift, Maths question 6 of 30, Section A. NTA dropped this question from the final key; it is left out of every count on this site.

Let

f: (-\infty,\infty)-\{0\} \to \mathbb{R}

be a differentiable function such that

f'(1)=\lim_{a\to\infty} a^2 f\left(\frac{1}{a}\right)

. Then

\lim_{a\to\infty} \frac{a(a+1)}{2}\tan^{-1}\left(\frac{1}{a}\right)+a^2-2\log_e a

is equal to

(1) $\frac{5}{2}+\frac{\pi}{8}$
(2) $\frac{3}{2}+\frac{\pi}{4}$
(3) $\frac{3}{8}+\frac{\pi}{4}$
(4) $\frac{3}{4}+\frac{\pi}{8}$

Official answer

Dropped by NTA (marks given to all)

NTA final key: NTA final key: DROP (question dropped).

Chapter: Limits and Derivatives
Topic: No close match in our taxonomy
Idea tested: No close match in our taxonomy