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Saturday, 31 October

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JEE Main 2024 · MathsMultiple choiceSingle correctMediumCalculation

JEE Main 6 April 2024, Shift 1, Maths Q5

Question 5 of 90 in this shift, Maths question 5 of 30, Section A.

For

\alpha, \beta \in \mathbb{R}

and a natural number

n

, let

A_r=\begin{vmatrix} r & 1 & \frac{n^2}{2}+\alpha \\ 2r & 2 & n^2-\beta \\ 3r-2 & 3 & \frac{n(3n-1)}{2} \end{vmatrix}

. Then

2A_{10}-A_8

is

(1) $0$
(2) $2n$
(3) $2\alpha+4\beta$
(4) $4\alpha+2\beta$ Official answer

Official answer

Option 4

NTA final key.

Chapter: Determinants
Topic: No close match in our taxonomy
Idea tested: No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.