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Saturday, 31 October

JEE Main 2024 · ChemistryNumerical answerNumerical valueMediumMulti-step

JEE Main 5 April 2024, Shift 2, Chemistry Q89

Question 89 of 90 in this shift, Chemistry question 29 of 30, Section B.

The product (C) in the following sequence of reactions has ________ π\pi bonds. n-propylbenzene (benzene ring bearing a three-carbon chain) →ΔKMnO4−KOH\xrightarrow[\Delta]{\mathrm{KMnO_4-KOH}} (A) →H3O+\xrightarrow{\mathrm{H_3O^+}} (B) →FeBr3Br2\xrightarrow[\mathrm{FeBr_3}]{\mathrm{Br_2}} (C)

The figure, in words

Starting material drawn as a benzene ring with a three-carbon zigzag alkyl chain (propyl group) attached; reagents over arrows: KMnO4−KOH\mathrm{KMnO_4-KOH}, Δ\Delta; then H3O+\mathrm{H_3O^+}; then Br2/FeBr3\mathrm{Br_2/FeBr_3}; intermediates labelled A, B, C.

Official answer

4

NTA final key.