JEE Main 2022 · ChemistryMultiple choiceSingle correctMediumApplication

JEE Main 26 June 2022, Shift 2, Chemistry Q72

Question 72 of 90 in this shift, Chemistry question 12 of 30, Section A.

Oxidation of toluene to benzaldehyde can be easily carried out with which of the following reagents?

(1) $\mathrm{CrO_3}$ /acetic acid, $\mathrm{H_3O^+}$
(2) $\mathrm{CrO_3}$ /acetic anhydride, $\mathrm{H_3O^+}$ Official answer
(3) $\mathrm{KMnO_4}$ /HCl, $\mathrm{H_3O^+}$
(4)CO/HCl, anhydrous $\mathrm{AlCl_3}$

Official answer

Option 2

NTA final key.

Chapter: Aldehydes, Ketones and Carboxylic Acids
Topic: Aromatic Hydrocarbons
Idea tested: Side-chain Oxidation

Same idea in other shifts

Asked 6× in all

4 Apr 2026, Shift 1 · Q72Consider the following sequence of reactions to give the major product (X) benzene…MediumNumerical valueHas a figure
5 Apr 2024, Shift 2 · Q89The product (C) in the following sequence of reactions has ________ $\pi$ bonds. n-propylbenzene (benzene ring bearing a three-carbon…MediumNumerical valueHas a figure
30 Jan 2024, Shift 1 · Q75In the given reactions, identify the reagent A and reagent B. [Scheme: toluene reacts via two routes to give benzaldehyde. Route 1: "A" +…MediumOtherHas a figure
10 Apr 2023, Shift 1 · Q74The major product ‘P’ formed in the given reaction is [structure: naphthalene ring bearing $\mathrm{CH_2CH_3}$ at one position of one…MediumDiagram basedHas a figure
4 Aug 2021, Shift 1 · Q45Identify P in the given chemical reaction i) $\mathrm{KMnO_4}$ , KOH, heat ii) $\mathrm{H_3O^+}$ EasyDiagram basedHas a figure

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.