JEE Main 4 April 2024, Shift 1, Physics Q58

Question 58 of 90 in this shift, Physics question 28 of 30, Section B.

A alternating current at any instant is given by

i = \left[6 + \sqrt{56}\sin(100\pi t + \pi/3)\right]

A. The rms value of the current is ________ A.

Official answer

NTA final key.

Chapter: Alternating Current
Topic: RMS and Peak Values
Idea tested: RMS Calculation via Integration

Same idea in other shifts

Asked 2× in all

26 Feb 2021, Shift 1 · Q14An alternating current is given by the equation $i=i_1\sin\omega t+i_2\cos\omega t$ . The rms current will be :EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.