JEE Main 2021 (26 Feb, Shift 1) Physics Q14: An…

Question

An alternating current is given by the equation $i=i_1\sin\omega t+i_2\cos\omega t$. The rms current will be :

Accepted Answer

Option 3: $\frac{1}{\sqrt{2}}\left(i_1^{2}+i_2^{2}\right)^{\frac{1}{2}}$

Answer

$\frac{1}{\sqrt{2}}(i_1+i_2)$

Answer

$\frac{1}{\sqrt{2}}(i_1+i_2)^{2}$

Answer

$\frac{1}{\sqrt{2}}\left(i_1^{2}+i_2^{2}\right)^{\frac{1}{2}}$

Answer

$\frac{1}{2}\left(i_1^{2}+i_2^{2}\right)^{\frac{1}{2}}$

JEE Main 26 February 2021, Shift 1, Physics Q14