JEE Main 2024 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 4 April 2024, Shift 1, Maths Q16

Question 16 of 90 in this shift, Maths question 16 of 30, Section A.

The vertices of a triangle are A

(-1, 3)

, B

(-2, 2)

and C

(3, -1)

. A new triangle is formed by shifting the sides of the triangle by one unit inwards. Then the equation of the side of the new triangle nearest to origin is :

(1) $x+y-(2-\sqrt{2})=0$ Official answer
(2) $x+y+(2-\sqrt{2})=0$
(3) $x-y-(2+\sqrt{2})=0$
(4) $-x+y-(2-\sqrt{2})=0$

Official answer

Option 1

NTA final key.

Chapter: Straight Lines
Topic: Straight Line Distance
Idea tested: Distance between parallel lines

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Asked 4× in all

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.