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Saturday, 31 October

JEE Main 2020 · MathsNumerical answerNumerical valueMediumCalculation

JEE Main 5 September 2020, Shift 1, Maths Q74

Question 74 of 75 in this shift, Maths question 24 of 25.

If the line, 2x−y+3=02x-y+3=0 is at a distance 15\frac{1}{\sqrt{5}} and 25\frac{2}{\sqrt{5}} from the lines 4x−2y+α=04x-2y+\alpha=0 and 6x−3y+β=06x-3y+\beta=0, respectively, then the sum of all possible values of α\alpha and β\beta is ________.

Official answer

30.00

NTA final key (Sep 2020).