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Saturday, 31 October

JEE Main 2023 · MathsMultiple choiceTwo statementsMediumApplication

JEE Main 13 April 2023, Shift 1, Maths Q7

Question 7 of 90 in this shift, Maths question 7 of 30, Section A.

Among (S1) : lim⁡n→∞1n2(2+4+6+……+2n)=1\lim_{n\to\infty}\frac{1}{n^2}(2+4+6+\ldots\ldots+2n)=1 (S2) : lim⁡n→∞1n16(115+215+315+……+n15)=116\lim_{n\to\infty}\frac{1}{n^{16}}\left(1^{15}+2^{15}+3^{15}+\ldots\ldots+n^{15}\right)=\frac{1}{16}
  1. (1)Only (S1) is true
  2. (2)Only (S2) is true
  3. (3)Both (S1) and (S2) are trueOfficial answer
  4. (4)Both (S1) and (S2) are false

Official answer

Option 3

NTA final key.