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Saturday, 31 October

JEE Main 2022 · MathsMultiple choiceSingle correctMediumMulti-step

JEE Main 26 July 2022, Shift 1, Maths Q10

Question 10 of 90 in this shift, Maths question 10 of 30, Section A.

If a=lim⁡n→∞∑k=1n2nn2+k2\mathrm{a} = \lim_{n \to \infty} \sum_{k=1}^{n} \dfrac{2n}{n^2 + k^2} and f(x)=1−cos⁡x1+cos⁡xf(x) = \sqrt{\dfrac{1 - \cos x}{1 + \cos x}}, x∈(0,1)x \in (0, 1), then :
  1. (1)22f(a2)=f′(a2)2\sqrt{2}f\left(\frac{\mathrm{a}}{2}\right) = f'\left(\frac{\mathrm{a}}{2}\right)
  2. (2)f(a2)f′(a2)=2f\left(\frac{\mathrm{a}}{2}\right) f'\left(\frac{\mathrm{a}}{2}\right) = \sqrt{2}
  3. (3)2f(a2)=f′(a2)\sqrt{2}f\left(\frac{\mathrm{a}}{2}\right) = f'\left(\frac{\mathrm{a}}{2}\right)Official answer
  4. (4)f(a2)=2f′(a2)f\left(\frac{\mathrm{a}}{2}\right) = \sqrt{2}f'\left(\frac{\mathrm{a}}{2}\right)

Official answer

Option 3

NTA final key.

Chapter
Integrals