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Saturday, 31 October

JEE Main 2023 · MathsMultiple choiceSingle correctHardMulti-step

JEE Main 12 April 2023, Shift 1, Maths Q9

Question 9 of 90 in this shift, Maths question 9 of 30, Section A.

If the local maximum value of the function f(x)=(3e2sin⁡x)sin⁡2xf(x)=\left(\frac{\sqrt{3e}}{2\sin x}\right)^{\sin^2 x}, x∈(0,π2)x\in\left(0,\frac{\pi}{2}\right), is ke\frac{k}{e}, then (ke)8+k8e5+k8\left(\frac{k}{e}\right)^8+\frac{k^8}{e^5}+k^8 is equal to
  1. (1)e5+e6+e11e^5+e^6+e^{11}
  2. (2)e3+e6+e10e^3+e^6+e^{10}
  3. (3)e3+e5+e11e^3+e^5+e^{11}
  4. (4)e3+e6+e11e^3+e^6+e^{11}Official answer

Official answer

Option 4

NTA final key.

Same idea in other shifts

Asked 2× in all
  1. 26 Aug 2021, Shift 2 · Q66The local maximum value of the function f(x)=(2x)x2f(x)=\left(\frac{2}{x}\right)^{x^2}, x>0x>0, is :MediumSingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.