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JEE Main 12 April 2023, Shift 1, Physics Q60

Question 60 of 90 in this shift, Physics question 30 of 30, Section B.

A common example of alpha decay is

^{238}_{92}\mathrm{U} \longrightarrow\, ^{234}_{90}\mathrm{Th} + {}_{2}\mathrm{He}^{4} + Q

Given :

^{238}_{92}\mathrm{U} = 238.05060\,\mathrm{u}

^{234}_{90}\mathrm{Th} = 234.04360\,\mathrm{u}

^{4}_{2}\mathrm{He} = 4.00260\,\mathrm{u}

and

1\,\mathrm{u} = 931.5\,\frac{\mathrm{MeV}}{c^2}

The energy released (Q) during the alpha decay of

^{238}_{92}\mathrm{U}

is ____ MeV

Official answer

NTA final key.

Same idea in other shifts