JEE Main 2023 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 11 April 2023, Shift 2, Physics Q32

Question 32 of 90 in this shift, Physics question 2 of 30, Section A.

The root mean square speed of molecules of nitrogen gas at

27^\circ\mathrm{C}

is approximately : (Given mass of a nitrogen molecule =

4.6\times10^{-26}\ \mathrm{kg}

and take Boltzmann constant

\mathrm{k_B} = 1.4\times10^{-23}\ \mathrm{JK^{-1}}

)

(1) $27.4\ \mathrm{m/s}$
(2) $91\ \mathrm{m/s}$
(3) $523\ \mathrm{m/s}$ Official answer
(4) $1260\ \mathrm{m/s}$

Official answer

Option 3

NTA final key.

Chapter: Kinetic Theory
Topic: Kinetic Theory of Gases
Idea tested: Molecular Speed Types

Same idea in other shifts

Asked 12× in all

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.