JEE Main 2023 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 6 April 2023, Shift 2, Physics Q39

Question 39 of 90 in this shift, Physics question 9 of 30, Section A.

The temperature of an ideal gas is increased from 200 K to 800 K. If r.m.s. speed of gas at 200 K is

v_0

. Then, r.m.s. speed of the gas at 800 K will be:

(1) $\frac{v_0}{4}$
(2) $2v_0$ Official answer
(3) $v_0$
(4) $4v_0$

Official answer

Option 2

NTA final key.

Chapter: Kinetic Theory
Topic: Kinetic Theory of Gases
Idea tested: Molecular Speed Types

Same idea in other shifts

Asked 12× in all

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.