JEE Main 2023 · PhysicsMultiple choiceSingle correctEasyApplication

JEE Main 10 April 2023, Shift 1, Physics Q31

Question 31 of 90 in this shift, Physics question 1 of 30, Section A.

A particle executes S.H.M. of amplitude A along

x

-axis. At

t = 0

, the position of the particle is

x = \frac{A}{2}

and it moves along positive

x

-axis. The displacement of particle in time

t

x = A\sin(wt + \delta)

, then the value

\delta

will be

(1) $\frac{\pi}{2}$
(2) $\frac{\pi}{3}$
(3) $\frac{\pi}{4}$
(4) $\frac{\pi}{6}$ Official answer

Official answer

Option 4

NTA final key.

Chapter: Oscillations
Topic: SHM Equations
Idea tested: Phase and Initial Conditions

Same idea in other shifts

Asked 4× in all

27 Jun 2022, Shift 1 · Q45The displacement of simple harmonic oscillator after 3 seconds starting from its mean position is equal to half of its amplitude. The time…EasySingle correct
25 Feb 2021, Shift 2 · Q8 $Y = A\sin(\omega t + \phi_0)$ is the time-displacement equation of a SHM. At $t = 0$ the displacement of the particle is…MediumSingle correct
22 Jul 2021, Shift 2 · Q9The motion of a mass on a spring, with spring constant K is as shown in figure. The equation of motion is given by…MediumSingle correctHas a figure

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.