JEE Main 2021 · PhysicsMultiple choiceSingle correctMediumApplication

JEE Main 25 February 2021, Shift 2, Physics Q8

Question 8 of 90 in this shift, Physics question 8 of 30, Section A.

Y = A\sin(\omega t + \phi_0)

is the time-displacement equation of a SHM. At

t = 0

the displacement of the particle is

Y = \frac{A}{2}

and it is moving along negative

x

-direction. Then the initial phase angle

\phi_0

will be :

(1) $\frac{\pi}{3}$
(2) $\frac{5\pi}{6}$ Official answer
(3) $\frac{\pi}{6}$
(4) $\frac{2\pi}{3}$

Official answer

Option 2

NTA final key.

Chapter: Oscillations
Topic: SHM Equations
Idea tested: Phase and Initial Conditions

Same idea in other shifts

Asked 4× in all

10 Apr 2023, Shift 1 · Q31A particle executes S.H.M. of amplitude A along $x$ -axis. At $t = 0$ , the position of the particle is $x = \frac{A}{2}$ and it moves along…EasySingle correct
27 Jun 2022, Shift 1 · Q45The displacement of simple harmonic oscillator after 3 seconds starting from its mean position is equal to half of its amplitude. The time…EasySingle correct
22 Jul 2021, Shift 2 · Q9The motion of a mass on a spring, with spring constant K is as shown in figure. The equation of motion is given by…MediumSingle correctHas a figure

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.