JEE Main 2023 · PhysicsNumerical answerNumerical valueMediumCalculation

JEE Main 8 April 2023, Shift 2, Physics Q55

Question 55 of 90 in this shift, Physics question 25 of 30, Section B.

A 600 pF capacitor is charged by 200 V supply. It is then disconnected from the supply and is connected to another uncharged 600 pF capacitor. Electrostatic energy lost in the process is ____________

\mu

Official answer

NTA final key.

Chapter: Electrostatic Potential and Capacitance
Topic: Parallel Plate Capacitors
Idea tested: Charge Sharing and Heat Loss

Same idea in other shifts

Asked 4× in all

3 Apr 2025, Shift 2 · Q38Using a battery, a 100 pF capacitor is charged to 60 V and then the battery is removed. After that, a second uncharged capacitor is…EasySingle correct
11 Apr 2023, Shift 1 · Q41A parallel plate capacitor of capacitance 2 F is charged to a potential V, The energy stored in the capacitor is $E_1$ . The capacitor is…EasySingle correct
2 Sep 2020, Shift 1 · Q23A $5\ \mu\mathrm{F}$ capacitor is charged fully by a 220 V supply. It is then disconnected from the supply and is connected in series to…MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.