JEE Main 2020 · PhysicsNumerical answerNumerical valueMediumCalculation

JEE Main 2 September 2020, Shift 1, Physics Q23

Question 23 of 75 in this shift, Physics question 23 of 25.

5\ \mu\mathrm{F}

capacitor is charged fully by a 220 V supply. It is then disconnected from the supply and is connected in series to another uncharged

2.5\ \mu\mathrm{F}

capacitor. If the energy change during the charge redistribution is

\frac{X}{100}

J then value of

X

to the nearest integer is ______.

Official answer

36.00

NTA final key (Sep 2020).

Chapter: Electrostatic Potential and Capacitance
Topic: Parallel Plate Capacitors
Idea tested: Charge Sharing and Heat Loss

Same idea in other shifts

Asked 4× in all

3 Apr 2025, Shift 2 · Q38Using a battery, a 100 pF capacitor is charged to 60 V and then the battery is removed. After that, a second uncharged capacitor is…EasySingle correct
8 Apr 2023, Shift 2 · Q55A 600 pF capacitor is charged by 200 V supply. It is then disconnected from the supply and is connected to another uncharged 600 pF…MediumNumerical value
11 Apr 2023, Shift 1 · Q41A parallel plate capacitor of capacitance 2 F is charged to a potential V, The energy stored in the capacitor is $E_1$ . The capacitor is…EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.