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JEE Main 2023 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 8 April 2023, Shift 2, Physics Q41

Question 41 of 90 in this shift, Physics question 11 of 30, Section A.

Electric potential at a point 'P' due to a point charge of

5\times10^{-9}

C is 50 V. The distance of 'P' from the point charge is: (Assume,

\frac{1}{4\pi\varepsilon_0} = 9 \times 10^{+9}\ \mathrm{Nm^2C^{-2}}

)

(1)90 cmOfficial answer
(2)3 cm
(3)9 cm
(4)0.9 cm

Official answer

Option 1

NTA final key.

Chapter: Electrostatic Potential and Capacitance
Topic: Electric Potential
Idea tested: Point Charge Potential

Same idea in other shifts

Asked 2× in all

3 Aug 2021, Shift 2 · Q11An electric charge $10^{-2}\,\mu\mathrm{C}$ is placed at the origin (0, 0) of X–Y coordinate system. The coordinates of two points A and B…EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.