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Friday, 9 October

JEE Main 2021 · PhysicsMultiple choiceSingle correctEasyApplication

JEE Main 3 August 2021, Shift 2, Physics Q11

Question 11 of 90 in this shift, Physics question 11 of 30, Section A.

An electric charge 10−2 μC10^{-2}\,\mu\mathrm{C} is placed at the origin (0, 0) of X–Y coordinate system. The coordinates of two points A and B are (2,2)(\sqrt{2},\sqrt{2}) and (2, 0), respectively. The potential difference between the point A and B will be -
  1. (1)44 V
  2. (2)00 VOfficial answer
  3. (3)88 V
  4. (4)66 V

Official answer

Option 2

NTA final key.

Same idea in other shifts

Asked 2× in all
  1. 8 Apr 2023, Shift 2 · Q41Electric potential at a point 'P' due to a point charge of 5×10−95\times10^{-9} C is 50 V. The distance of 'P' from the point charge is:…EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.