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Friday, 9 October

JEE Main 2022 · MathsNumerical answerNumerical valueMediumMulti-step

JEE Main 29 June 2022, Shift 1, Maths Q28

Question 28 of 90 in this shift, Maths question 28 of 30, Section B.

Let H:x2a2−y2b2=1H: \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1, a>0,b>0a > 0, b > 0, be a hyperbola such that the sum of lengths of the transverse and the conjugate axes is 4(22+14)4(2\sqrt{2} + \sqrt{14}). If the eccentricity H is 112\frac{\sqrt{11}}{2}, then the value of a2+b2a^2 + b^2 is equal to ____________.

Official answer

88

NTA final key (2022 Session 1).

Chapter
Conic Sections
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.