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Friday, 9 October

JEE Main 2022 · MathsNumerical answerNumerical valueMediumMulti-step

JEE Main 29 June 2022, Shift 1, Maths Q27

Question 27 of 90 in this shift, Maths question 27 of 30, Section B.

Let c,k∈Rc, k \in \mathbf{R}. If f(x)=(c+1)x2+(1−c2)x+2kf(x) = (c + 1)x^2 + (1 - c^2)x + 2k and f(x+y)=f(x)+f(y)−xyf(x + y) = f(x) + f(y) - xy, for all x,y∈Rx, y \in \mathbf{R}, then the value of ∣2(f(1)+f(2)+f(3)+……+f(20))∣|2(f(1) + f(2) + f(3) + \ldots\ldots + f(20))| is equal to ____________.

Official answer

3395

NTA final key (2022 Session 1).

Topic
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Idea tested
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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.