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JEE Main 2022 · PhysicsNumerical answerNumerical valueMediumCalculation

JEE Main 27 June 2022, Shift 2, Physics Q56

Question 56 of 90 in this shift, Physics question 26 of 30, Section B.

The current density in a cylindrical wire of radius

r

= 4.0 mm is

1.0 \times 10^{6}

A/m

^2

. The current through the outer portion of the wire between radial distances

\frac{r}{2}

and

r

is

x\pi

A; where

x

is ________.

Official answer

12

NTA final key.

Chapter: Current Electricity
Topic: Ohm's Law and Resistance
Idea tested: Integrating Non-Uniform Current Density

Same idea in other shifts

Asked 2× in all

27 Jun 2022, Shift 1 · Q56The current density in a cylindrical wire of radius 4 mm is $4\times10^6\ \mathrm{Am^{-2}}$ . The current through the outer portion of the…MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.