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JEE Main 2022 · PhysicsNumerical answerNumerical valueMediumCalculation

JEE Main 27 June 2022, Shift 1, Physics Q56

Question 56 of 90 in this shift, Physics question 26 of 30, Section B.

The current density in a cylindrical wire of radius 4 mm is

4\times10^6\ \mathrm{Am^{-2}}

. The current through the outer portion of the wire between radial distances

\frac{R}{2}

and R is __________

\pi

A.

Official answer

48

NTA final key.

Chapter: Current Electricity
Topic: Ohm's Law and Resistance
Idea tested: Integrating Non-Uniform Current Density

Same idea in other shifts

Asked 2× in all

27 Jun 2022, Shift 2 · Q56The current density in a cylindrical wire of radius $r$ = 4.0 mm is $1.0 \times 10^{6}$ A/m $^2$ . The current through the outer portion of…MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.