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Saturday, 31 October

JEE Main 2022 · ChemistryMultiple choiceDiagram basedHardApplication

JEE Main 25 June 2022, Shift 2, Chemistry Q78

Question 78 of 90 in this shift, Chemistry question 18 of 30, Section A.

The major product formed in the following reaction, is [drawn: zigzag carbon chain with a methyl-type branch at the left end, ending in OH] + [drawn: six-membered ring with one O and a double bond on the ring edge next to the O] →H+\xrightarrow{\mathrm{H^+}}

The figure, in words

Reactants: a branched skeletal-line alcohol (chain ends in OH) plus a six-membered ring with one O and a C=C double bond on the ring edge next to O; arrow with H+ above. Options are skeletal-line structures.
  1. (1)[figure: branched zigzag chain ending in O, bonded to a ring carbon of a six-membered ring containing one O; the attached ring carbon is separated from the ring O by one ring carbon]
  2. (2)[figure: branched zigzag chain ending in O, then an unbranched zigzag chain with one C=C, ending in OH]
  3. (3)[figure: branched zigzag chain ending in O, then an unbranched zigzag chain ending in an aldehyde group (C=O with H)]
  4. (4)[figure: branched zigzag chain ending in O, bonded to the ring carbon next to the ring O of a six-membered ring containing one O]Official answer

Official answer

Option 4

NTA final key.

Chapter
Alcohols, Phenols and Ethers
Topic
No close match in our taxonomy
Idea tested
No close match in our taxonomy

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. This question needs a figure we do not reproduce; it is described in words above. Lumi analyses 108 of the 174 JEE Main shifts held from 2017 to 2026.