JEE Main 2022 · PhysicsMultiple choiceSingle correctEasyApplication

JEE Main 24 June 2022, Shift 1, Physics Q38

Question 38 of 90 in this shift, Physics question 8 of 30, Section A.

A vertical electric field of magnitude

4.9\times10^{5}

N/C just prevents a water droplet of a mass 0.1 g from falling. The value of charge on the droplet will be : (Given

g=9.8\ \mathrm{m/s^2}

)

(1) $1.6\times10^{-9}\ \mathrm{C}$
(2) $2.0\times10^{-9}\ \mathrm{C}$ Official answer
(3) $3.2\times10^{-9}\ \mathrm{C}$
(4) $0.5\times10^{-9}\ \mathrm{C}$

Official answer

Option 2

NTA final key (2022 Session 1).

Chapter: Electric Charges and Fields
Topic: Electric Field
Idea tested: Equilibrium of Suspended Charges

Same topic in other shifts

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Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.