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Saturday, 31 October

JEE Main 2022 · ChemistryMultiple choiceOtherMediumMulti-step

JEE Main 28 July 2022, Shift 2, Chemistry Q49

Question 49 of 90 in this shift, Chemistry question 19 of 30, Section A.

The formulas of A and B for the following reaction sequence Fructose →H3O+HCN\xrightarrow[\mathrm{H_3O^+}]{\mathrm{HCN}} A Fructose →(ii) HI/P(i) NaBH4\xrightarrow[\text{(ii) HI/P}]{\text{(i) } \mathrm{NaBH_4}} B are

The figure, in words

Reaction scheme: fructose branches into two routes: (HCN, then H3O+) giving A, and (i) NaBH4, (ii) HI/P giving B.
  1. (1)A = C7H14O8\mathrm{C_7H_{14}O_8}, B = C6H14\mathrm{C_6H_{14}}Official answer
  2. (2)A = C7H13O7\mathrm{C_7H_{13}O_7}, B = C7H14O\mathrm{C_7H_{14}O}
  3. (3)A = C7H12O8\mathrm{C_7H_{12}O_8}, B = C6H14\mathrm{C_6H_{14}}
  4. (4)A = C7H14O8\mathrm{C_7H_{14}O_8}, B = C6H14O6\mathrm{C_6H_{14}O_6}

Official answer

Option 1

NTA final key.